Дана таблица сотрудников с полями: name, department, salary.
Верните Top-N имён сотрудников по зарплате из указанного отдела.
def top_n_employees(data: dict, department: str, n: int) -> list[str]:data = {"name": ["Alice","Bob","Charlie","Diana","Eve"], "department": ["IT","IT","HR","IT","HR"], "salary": [120000,95000,80000,110000,90000]}
top_n_employees(data, "IT", 2) → ["Alice", "Diana"]Если зарплаты равны — сортировать по алфавиту имени.
data = {"name":["Alice","Bob","Charlie","Diana","Eve"],"department":["IT","IT","HR","IT","HR"],"salary":[120000,95000,80000,110000,90000]}department = "IT"n = 2["Alice","Diana"]data = {"name":["Alice","Bob","Charlie","Diana","Eve"],"department":["IT","IT","HR","IT","HR"],"salary":[120000,95000,80000,110000,90000]}department = "HR"n = 1["Eve"]data = {"name":["A","B","C"],"department":["X","X","X"],"salary":[100,100,100]}department = "X"n = 2["A","B"]